hasil dari a+b+c adalah
Jawab:
12a+108=180
12a=180-108
12a=72
a=72/12
a=6
56+5(6)+2b=180
56+30+2b=180
86+2b=180
2b=180-86
2b=94
b=94/2
b=47
72+56+4c=180
128+4c=180
4c=180-128
4c=52
c=52/4
c=13
a+b+c = 6+47+13 = 66
12a + 108 = 180 (sudut berpelurus)
12a = 180 - 108
12a = 72
a = 72/12
a = 6
56 + (5a + 2b) = 180 (sudut berpelurus)
56 + 5(6) + 2b = 180
56 + 30 + 2b = 180
86 + 2b = 180
2b = 180 - 86
2b = 94
b = 94/2
b = 47
12a + 4c + 56 = 180 (jumlah sudut sudut segitiga)
12(6) + 4c + 56 = 180
72 + 4c + 56 = 180
128 + 4c = 180
4c = 180 - 128
4c = 52
c = 52/4
c = 13
a + b + c
= 6 + 47 + 13
= 66
[answer.2.content]
